What is the factor at 20 to 25 deg.? And is it definitely this factor X(times) total weight for each rope, and not just half?
Bill
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What is the factor at 20 to 25 deg.? And is it definitely this factor X(times) total weight for each rope, and not just half?
Bill
I hear you there. My grad school work is making computer models and tweaking them to match experimental test results.
That is usually why I make huge saftey factors when I am figuring the load rating of my suspension system.
My thought is more of an optimation thing than anything else. I know that my current system will hold me just fine. But if I can make a small change, mainly the type of knot I use to attach my rope from my hammock to the decending ring, and get an increase in load it can handle. Then the engineer in me wants to do it.
Think of it as getting the most out of what I am currently using.
Plus you never know, maybe one of these days my car will want it's own hammock.:p
Basic trig - force on the support is the hypoteneus of a triangle.
h = (.5 x user weight) / sin(support angle)
Youngblood posted an Excel spreadsheet in the Files section of Yahoo hammockcamping. You plug in your weight and it spits out the force for various angles. You need to be logged into Yahoo to access the files.
i never was good at all that math stuff. if i want to cut the perfect angle on a 2x4 brace, i lay it where it goes & mark it... BAM!!! perfect:rolleyes:
You don't have to teach me Trig. I taught trig at University. I was really referring to learning more complex concepts.
EDIT:Sorry just realized it seems as though I was attacking you. I was just explaining that I wanted to actually learn statics, not just the rudiments.
Is there another static equation that fits better? What's left to study up on? (Seriously asking...not being sarcastic)Quote:
Originally Posted by lvleph